Solve y=x+y/3

$$y = \frac { x + y } { 3 }$$

Solve for x

$$x=2y$$

Steps for Solving Linear Equation

Divide each term of x+y by 3 to get \frac{1}{3}x+\frac{1}{3}y.

$$y=\frac{1}{3}x+\frac{1}{3}y$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{3}x+\frac{1}{3}y=y$$

Subtract \frac{1}{3}y from both sides.

$$\frac{1}{3}x=y-\frac{1}{3}y$$

Combine y and -\frac{1}{3}y to get \frac{2}{3}y.

$$\frac{1}{3}x=\frac{2}{3}y$$

The equation is in standard form.

$$\frac{1}{3}x=\frac{2y}{3}$$

Multiply both sides by 3.

$$\frac{\frac{1}{3}x}{\frac{1}{3}}=\frac{2y}{\frac{1}{3}\times 3}$$

Dividing by \frac{1}{3} undoes the multiplication by \frac{1}{3}.

$$x=\frac{2y}{\frac{1}{3}\times 3}$$

Divide \frac{2y}{3} by \frac{1}{3} by multiplying \frac{2y}{3} by the reciprocal of \frac{1}{3}.

$$x=2y$$

Solve for y

$$y=\frac{x}{2}$$

Steps for Solving Linear Equation

Divide each term of x+y by 3 to get \frac{1}{3}x+\frac{1}{3}y.

$$y=\frac{1}{3}x+\frac{1}{3}y$$

Subtract \frac{1}{3}y from both sides.

$$y-\frac{1}{3}y=\frac{1}{3}x$$

Combine y and -\frac{1}{3}y to get \frac{2}{3}y.

$$\frac{2}{3}y=\frac{1}{3}x$$

The equation is in standard form.

$$\frac{2}{3}y=\frac{x}{3}$$

Divide both sides of the equation by \frac{2}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{2}{3}y}{\frac{2}{3}}=\frac{x}{\frac{2}{3}\times 3}$$

Dividing by \frac{2}{3} undoes the multiplication by \frac{2}{3}.

$$y=\frac{x}{\frac{2}{3}\times 3}$$

Divide \frac{x}{3} by \frac{2}{3} by multiplying \frac{x}{3} by the reciprocal of \frac{2}{3}.

$$y=\frac{x}{2}$$