Solve y=b^2+2b-8/4

$$y = \frac { b ^ { 2 } + 2 b - 8 } { 4 }$$

Solve for y

$$y=\frac{\left(b-2\right)\left(b+4\right)}{4}$$

Solution Steps

Divide each term of b^{2}+2b-8 by 4 to get \frac{1}{4}b^{2}+\frac{1}{2}b-2.

$$y=\frac{1}{4}b^{2}+\frac{1}{2}b-2$$

Solve for b (complex solution)

$$b=\sqrt{4y+9}-1$$

$$b=-\sqrt{4y+9}-1$$

Solve for b

$$b=\sqrt{4y+9}-1$$

$$b=-\sqrt{4y+9}-1\text{, }y\geq -\frac{9}{4}$$