Solve y=4x^3-2x+1/9x-2;quadx=-2

$$y = \frac { 4 x ^ { 3 } - 2 x + 1 } { 9 x - 2 } ; \quad x = - 2$$

Solve for y, x

$$x=-2$$

$$y = \frac{27}{20} = 1\frac{7}{20} = 1.35$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$y=\frac{4\left(-2\right)^{3}-2\left(-2\right)+1}{9\left(-2\right)-2}$$

Calculate -2 to the power of 3 and get -8.

$$y=\frac{4\left(-8\right)-2\left(-2\right)+1}{9\left(-2\right)-2}$$

Multiply 4 and -8 to get -32.

$$y=\frac{-32-2\left(-2\right)+1}{9\left(-2\right)-2}$$

Multiply -2 and -2 to get 4.

$$y=\frac{-32+4+1}{9\left(-2\right)-2}$$

Add -32 and 4 to get -28.

$$y=\frac{-28+1}{9\left(-2\right)-2}$$

Add -28 and 1 to get -27.

$$y=\frac{-27}{9\left(-2\right)-2}$$

Multiply 9 and -2 to get -18.

$$y=\frac{-27}{-18-2}$$

Subtract 2 from -18 to get -20.

$$y=\frac{-27}{-20}$$

Fraction \frac{-27}{-20} can be simplified to \frac{27}{20} by removing the negative sign from both the numerator and the denominator.

$$y=\frac{27}{20}$$

The system is now solved.

$$y=\frac{27}{20} x=-2$$