Solve y=4/x^2+b

$$y = \frac { 4 } { x ^ { 2 } } + b$$

Solve for b

$$b=y-\frac{4}{x^{2}}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by x^{2}.

$$yx^{2}=4+x^{2}b$$

Swap sides so that all variable terms are on the left hand side.

$$4+x^{2}b=yx^{2}$$

Subtract 4 from both sides.

$$x^{2}b=yx^{2}-4$$

Divide both sides by x^{2}.

$$\frac{x^{2}b}{x^{2}}=\frac{yx^{2}-4}{x^{2}}$$

Dividing by x^{2} undoes the multiplication by x^{2}.

$$b=\frac{yx^{2}-4}{x^{2}}$$

Divide yx^{2}-4 by x^{2}.

$$b=y-\frac{4}{x^{2}}$$

Solve for x (complex solution)

$$x=-2i\left(b-y\right)^{-\frac{1}{2}}$$

$$x=2i\left(b-y\right)^{-\frac{1}{2}}\text{, }y\neq b$$

Solve for x

$$x=2\sqrt{-\frac{1}{b-y}}$$

$$x=-2\sqrt{-\frac{1}{b-y}}\text{, }y>b$$