Solve for y
y = \frac{7}{3} = 2\frac{1}{3} \approx 2.333333333
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y≔\frac{7}{3}
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y=\frac{4}{3}+\frac{3}{3}
Convert 1 to fraction \frac{3}{3}.
y=\frac{4+3}{3}
Since \frac{4}{3} and \frac{3}{3} have the same denominator, add them by adding their numerators.
y=\frac{7}{3}
Add 4 and 3 to get 7.
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