Solve y=3ab+3/6c

$$y = \frac { 3 a b + 3 } { 6 c }$$

Solve for a

$$\left\{\begin{matrix}a=-\frac{1-2cy}{b}\text{, }&b\neq 0\text{ and }c\neq 0\\a\in \mathrm{R}\text{, }&y=\frac{1}{2c}\text{ and }c\neq 0\text{ and }b=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6c.

$$y\times 6c=3ab+3$$

Swap sides so that all variable terms are on the left hand side.

$$3ab+3=y\times 6c$$

Subtract 3 from both sides.

$$3ab=y\times 6c-3$$

The equation is in standard form.

$$3ba=6cy-3$$

Divide both sides by 3b.

$$\frac{3ba}{3b}=\frac{6cy-3}{3b}$$

Dividing by 3b undoes the multiplication by 3b.

$$a=\frac{6cy-3}{3b}$$

Divide 6yc-3 by 3b.

$$a=\frac{2cy-1}{b}$$

Solve for b

$$\left\{\begin{matrix}b=-\frac{1-2cy}{a}\text{, }&a\neq 0\text{ and }c\neq 0\\b\in \mathrm{R}\text{, }&y=\frac{1}{2c}\text{ and }c\neq 0\text{ and }a=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6c.

$$y\times 6c=3ab+3$$

Swap sides so that all variable terms are on the left hand side.

$$3ab+3=y\times 6c$$

Subtract 3 from both sides.

$$3ab=y\times 6c-3$$

The equation is in standard form.

$$3ab=6cy-3$$

Divide both sides by 3a.

$$\frac{3ab}{3a}=\frac{6cy-3}{3a}$$

Dividing by 3a undoes the multiplication by 3a.

$$b=\frac{6cy-3}{3a}$$

Divide 6yc-3 by 3a.

$$b=\frac{2cy-1}{a}$$