Solve for x
x=-\frac{7y-3}{y+1}
y\neq -1
Solve for y
y=-\frac{x-3}{x+7}
x\neq -7
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y\left(x+7\right)=3-x
Variable x cannot be equal to -7 since division by zero is not defined. Multiply both sides of the equation by x+7.
yx+7y=3-x
Use the distributive property to multiply y by x+7.
yx+7y+x=3
Add x to both sides.
yx+x=3-7y
Subtract 7y from both sides.
\left(y+1\right)x=3-7y
Combine all terms containing x.
\frac{\left(y+1\right)x}{y+1}=\frac{3-7y}{y+1}
Divide both sides by y+1.
x=\frac{3-7y}{y+1}
Dividing by y+1 undoes the multiplication by y+1.
x=\frac{3-7y}{y+1}\text{, }x\neq -7
Variable x cannot be equal to -7.
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