Solve y=3/x-2+1

$$y = \frac { 3 } { x - 2 } + 1$$

Solve for x

$$x=-\frac{2y+1}{1-y}$$

$$y\neq 1$$

Steps for Solving Linear Equation

Variable x cannot be equal to 2 since division by zero is not defined. Multiply both sides of the equation by x-2.

$$y\left(x-2\right)=3+x-2$$

Use the distributive property to multiply y by x-2.

$$yx-2y=3+x-2$$

Subtract 2 from 3 to get 1.

$$yx-2y=1+x$$

Subtract x from both sides.

$$yx-2y-x=1$$

Add 2y to both sides.

$$yx-x=1+2y$$

Combine all terms containing x.

$$\left(y-1\right)x=1+2y$$

The equation is in standard form.

$$\left(y-1\right)x=2y+1$$

Divide both sides by y-1.

$$\frac{\left(y-1\right)x}{y-1}=\frac{2y+1}{y-1}$$

Dividing by y-1 undoes the multiplication by y-1.

$$x=\frac{2y+1}{y-1}$$

Variable x cannot be equal to 2.

$$x=\frac{2y+1}{y-1}\text{, }x\neq 2$$

Solve for y

$$y=\frac{x+1}{x-2}$$

$$x\neq 2$$