Solve for x
x=-\frac{y}{2-3y}
y\neq \frac{2}{3}
Solve for y
y=\frac{2x}{3x-1}
x\neq \frac{1}{3}
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y\left(3x-1\right)=2x
Variable x cannot be equal to \frac{1}{3} since division by zero is not defined. Multiply both sides of the equation by 3x-1.
3yx-y=2x
Use the distributive property to multiply y by 3x-1.
3yx-y-2x=0
Subtract 2x from both sides.
3yx-2x=y
Add y to both sides. Anything plus zero gives itself.
\left(3y-2\right)x=y
Combine all terms containing x.
\frac{\left(3y-2\right)x}{3y-2}=\frac{y}{3y-2}
Divide both sides by 3y-2.
x=\frac{y}{3y-2}
Dividing by 3y-2 undoes the multiplication by 3y-2.
x=\frac{y}{3y-2}\text{, }x\neq \frac{1}{3}
Variable x cannot be equal to \frac{1}{3}.
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