Solve y=1/3(x-1)+3

$$y = \frac { 1 } { 3 } ( x - 1 ) + 3$$

Solve for x

$$x=3y-8$$

Steps for Solving Linear Equation

Use the distributive property to multiply \frac{1}{3} by x-1.

$$y=\frac{1}{3}x-\frac{1}{3}+3$$

Add -\frac{1}{3} and 3 to get \frac{8}{3}.

$$y=\frac{1}{3}x+\frac{8}{3}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{3}x+\frac{8}{3}=y$$

Subtract \frac{8}{3} from both sides.

$$\frac{1}{3}x=y-\frac{8}{3}$$

Multiply both sides by 3.

$$\frac{\frac{1}{3}x}{\frac{1}{3}}=\frac{y-\frac{8}{3}}{\frac{1}{3}}$$

Dividing by \frac{1}{3} undoes the multiplication by \frac{1}{3}.

$$x=\frac{y-\frac{8}{3}}{\frac{1}{3}}$$

Divide y-\frac{8}{3} by \frac{1}{3} by multiplying y-\frac{8}{3} by the reciprocal of \frac{1}{3}.

$$x=3y-8$$

Solve for y

$$y=\frac{x+8}{3}$$

Solution Steps

Use the distributive property to multiply \frac{1}{3} by x-1.

$$y=\frac{1}{3}x-\frac{1}{3}+3$$

Add -\frac{1}{3} and 3 to get \frac{8}{3}.

$$y=\frac{1}{3}x+\frac{8}{3}$$