Solve for y
y=\frac{\left(x+3\right)^{2}}{5}
Solve for x (complex solution)
x=-\left(\sqrt{5y}+3\right)
x=\sqrt{5y}-3
Solve for x
x=-\left(\sqrt{5y}+3\right)
x=\sqrt{5y}-3\text{, }y\geq 0
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y=\frac{x^{2}+6x+9}{5}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+3\right)^{2}.
y=\frac{1}{5}x^{2}+\frac{6}{5}x+\frac{9}{5}
Divide each term of x^{2}+6x+9 by 5 to get \frac{1}{5}x^{2}+\frac{6}{5}x+\frac{9}{5}.
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