Solve for x (complex solution)
\left\{\begin{matrix}x=\frac{y+3}{2z}\text{, }&z\neq 0\\x\in \mathrm{C}\text{, }&y=-3\text{ and }z=0\end{matrix}\right.
Solve for x
\left\{\begin{matrix}x=\frac{y+3}{2z}\text{, }&z\neq 0\\x\in \mathrm{R}\text{, }&y=-3\text{ and }z=0\end{matrix}\right.
Solve for y
y=2xz-3
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2xz-3=y
Swap sides so that all variable terms are on the left hand side.
2xz=y+3
Add 3 to both sides.
2zx=y+3
The equation is in standard form.
\frac{2zx}{2z}=\frac{y+3}{2z}
Divide both sides by 2z.
x=\frac{y+3}{2z}
Dividing by 2z undoes the multiplication by 2z.
2xz-3=y
Swap sides so that all variable terms are on the left hand side.
2xz=y+3
Add 3 to both sides.
2zx=y+3
The equation is in standard form.
\frac{2zx}{2z}=\frac{y+3}{2z}
Divide both sides by 2z.
x=\frac{y+3}{2z}
Dividing by 2z undoes the multiplication by 2z.
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