y = 10 \cdot 15+(x-10)+15 \times 8 \times 80 \%
Solve for x
x=y-236
Solve for y
y=x+236
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y=150+x-10+120\times \frac{80}{100}
Do the multiplications.
y=140+x+120\times \frac{80}{100}
Subtract 10 from 150 to get 140.
y=140+x+120\times \frac{4}{5}
Reduce the fraction \frac{80}{100} to lowest terms by extracting and canceling out 20.
y=140+x+96
Multiply 120 and \frac{4}{5} to get 96.
y=236+x
Add 140 and 96 to get 236.
236+x=y
Swap sides so that all variable terms are on the left hand side.
x=y-236
Subtract 236 from both sides.
y=150+x-10+120\times \frac{80}{100}
Do the multiplications.
y=140+x+120\times \frac{80}{100}
Subtract 10 from 150 to get 140.
y=140+x+120\times \frac{4}{5}
Reduce the fraction \frac{80}{100} to lowest terms by extracting and canceling out 20.
y=140+x+96
Multiply 120 and \frac{4}{5} to get 96.
y=236+x
Add 140 and 96 to get 236.
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