Solve y=-7/3x^+6

$$y = - \frac{ 7 }{ 3 } { x }^{ } +6$$

Solve for x

$$x=\frac{18-3y}{7}$$

Steps for Solving Linear Equation

Calculate x to the power of 1 and get x.

$$y=-\frac{7}{3}x+6$$

Swap sides so that all variable terms are on the left hand side.

$$-\frac{7}{3}x+6=y$$

Subtract 6 from both sides.

$$-\frac{7}{3}x=y-6$$

Divide both sides of the equation by -\frac{7}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{7}{3}x}{-\frac{7}{3}}=\frac{y-6}{-\frac{7}{3}}$$

Dividing by -\frac{7}{3} undoes the multiplication by -\frac{7}{3}.

$$x=\frac{y-6}{-\frac{7}{3}}$$

Divide y-6 by -\frac{7}{3} by multiplying y-6 by the reciprocal of -\frac{7}{3}.

$$x=\frac{18-3y}{7}$$

Solve for y

$$y=-\frac{7x}{3}+6$$

Solution Steps

Calculate x to the power of 1 and get x.

$$y=-\frac{7}{3}x+6$$