Solve for y
y=-\frac{x^{3}}{27}+x^{2}
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y=x^{2}-\left(\frac{1}{3}\right)^{3}x^{3}
Expand \left(\frac{1}{3}x\right)^{3}.
y=x^{2}-\frac{1}{27}x^{3}
Calculate \frac{1}{3} to the power of 3 and get \frac{1}{27}.
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