Solve y=1/5x-9

$$y = \frac{ 1 }{ 5x-9 }$$

Solve for x

$$x=\frac{9}{5}+\frac{1}{5y}$$

$$y\neq 0$$

Steps for Solving Linear Equation

Variable x cannot be equal to \frac{9}{5} since division by zero is not defined. Multiply both sides of the equation by 5x-9.

$$y\left(5x-9\right)=1$$

Use the distributive property to multiply y by 5x-9.

$$5yx-9y=1$$

Add 9y to both sides.

$$5yx=1+9y$$

The equation is in standard form.

$$5yx=9y+1$$

Divide both sides by 5y.

$$\frac{5yx}{5y}=\frac{9y+1}{5y}$$

Dividing by 5y undoes the multiplication by 5y.

$$x=\frac{9y+1}{5y}$$

Divide 1+9y by 5y.

$$x=\frac{9}{5}+\frac{1}{5y}$$

Variable x cannot be equal to \frac{9}{5}.

$$x=\frac{9}{5}+\frac{1}{5y}\text{, }x\neq \frac{9}{5}$$

Solve for y

$$y=\frac{1}{5x-9}$$

$$x\neq \frac{9}{5}$$