Solve y+4=1/3(x+2)

$$y + 4 = \frac { 1 } { 3 } ( x + 2 )$$

Solve for x

$$x=3y+10$$

Steps for Solving Linear Equation

Use the distributive property to multiply \frac{1}{3} by x+2.

$$y+4=\frac{1}{3}x+\frac{2}{3}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{3}x+\frac{2}{3}=y+4$$

Subtract \frac{2}{3} from both sides.

$$\frac{1}{3}x=y+4-\frac{2}{3}$$

Subtract \frac{2}{3} from 4 to get \frac{10}{3}.

$$\frac{1}{3}x=y+\frac{10}{3}$$

Multiply both sides by 3.

$$\frac{\frac{1}{3}x}{\frac{1}{3}}=\frac{y+\frac{10}{3}}{\frac{1}{3}}$$

Dividing by \frac{1}{3} undoes the multiplication by \frac{1}{3}.

$$x=\frac{y+\frac{10}{3}}{\frac{1}{3}}$$

Divide y+\frac{10}{3} by \frac{1}{3} by multiplying y+\frac{10}{3} by the reciprocal of \frac{1}{3}.

$$x=3y+10$$

Solve for y

$$y=\frac{x-10}{3}$$

Solution Steps

Use the distributive property to multiply \frac{1}{3} by x+2.

$$y+4=\frac{1}{3}x+\frac{2}{3}$$

Subtract 4 from both sides.

$$y=\frac{1}{3}x+\frac{2}{3}-4$$

Subtract 4 from \frac{2}{3} to get -\frac{10}{3}.

$$y=\frac{1}{3}x-\frac{10}{3}$$