Solve y+2=-1/3(x+4)

$$y + 2 = - \frac { 1 } { 3 } ( x + 4 )$$

Solve for x

$$x=-3y-10$$

Steps for Solving Linear Equation

Use the distributive property to multiply -\frac{1}{3} by x+4.

$$y+2=-\frac{1}{3}x-\frac{4}{3}$$

Swap sides so that all variable terms are on the left hand side.

$$-\frac{1}{3}x-\frac{4}{3}=y+2$$

Add \frac{4}{3} to both sides.

$$-\frac{1}{3}x=y+2+\frac{4}{3}$$

Add 2 and \frac{4}{3} to get \frac{10}{3}.

$$-\frac{1}{3}x=y+\frac{10}{3}$$

Multiply both sides by -3.

$$\frac{-\frac{1}{3}x}{-\frac{1}{3}}=\frac{y+\frac{10}{3}}{-\frac{1}{3}}$$

Dividing by -\frac{1}{3} undoes the multiplication by -\frac{1}{3}.

$$x=\frac{y+\frac{10}{3}}{-\frac{1}{3}}$$

Divide y+\frac{10}{3} by -\frac{1}{3} by multiplying y+\frac{10}{3} by the reciprocal of -\frac{1}{3}.

$$x=-3y-10$$

Solve for y

$$y=\frac{-x-10}{3}$$

Solution Steps

Use the distributive property to multiply -\frac{1}{3} by x+4.

$$y+2=-\frac{1}{3}x-\frac{4}{3}$$

Subtract 2 from both sides.

$$y=-\frac{1}{3}x-\frac{4}{3}-2$$

Subtract 2 from -\frac{4}{3} to get -\frac{10}{3}.

$$y=-\frac{1}{3}x-\frac{10}{3}$$