Solve y+1=-3/5(x-4)

$$y + 1 = - \frac { 3 } { 5 } ( x - 4 )$$

Solve for x

$$x=\frac{7-5y}{3}$$

Steps for Solving Linear Equation

Use the distributive property to multiply -\frac{3}{5} by x-4.

$$y+1=-\frac{3}{5}x+\frac{12}{5}$$

Swap sides so that all variable terms are on the left hand side.

$$-\frac{3}{5}x+\frac{12}{5}=y+1$$

Subtract \frac{12}{5} from both sides.

$$-\frac{3}{5}x=y+1-\frac{12}{5}$$

Subtract \frac{12}{5} from 1 to get -\frac{7}{5}.

$$-\frac{3}{5}x=y-\frac{7}{5}$$

Divide both sides of the equation by -\frac{3}{5}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{3}{5}x}{-\frac{3}{5}}=\frac{y-\frac{7}{5}}{-\frac{3}{5}}$$

Dividing by -\frac{3}{5} undoes the multiplication by -\frac{3}{5}.

$$x=\frac{y-\frac{7}{5}}{-\frac{3}{5}}$$

Divide y-\frac{7}{5} by -\frac{3}{5} by multiplying y-\frac{7}{5} by the reciprocal of -\frac{3}{5}.

$$x=\frac{7-5y}{3}$$

Solve for y

$$y=\frac{7-3x}{5}$$

Solution Steps

Use the distributive property to multiply -\frac{3}{5} by x-4.

$$y+1=-\frac{3}{5}x+\frac{12}{5}$$

Subtract 1 from both sides.

$$y=-\frac{3}{5}x+\frac{12}{5}-1$$

Subtract 1 from \frac{12}{5} to get \frac{7}{5}.

$$y=-\frac{3}{5}x+\frac{7}{5}$$