Solve y+1/3x-2=0

$$y + \frac { 1 } { 3 } x - 2 = 0$$

Solve for x

$$x=6-3y$$

Steps for Solving Linear Equation

Subtract y from both sides. Anything subtracted from zero gives its negation.

$$\frac{1}{3}x-2=-y$$

Add 2 to both sides.

$$\frac{1}{3}x=-y+2$$

The equation is in standard form.

$$\frac{1}{3}x=2-y$$

Multiply both sides by 3.

$$\frac{\frac{1}{3}x}{\frac{1}{3}}=\frac{2-y}{\frac{1}{3}}$$

Dividing by \frac{1}{3} undoes the multiplication by \frac{1}{3}.

$$x=\frac{2-y}{\frac{1}{3}}$$

Divide -y+2 by \frac{1}{3} by multiplying -y+2 by the reciprocal of \frac{1}{3}.

$$x=6-3y$$

Solve for y

$$y=-\frac{x}{3}+2$$

Solution Steps

Subtract \frac{1}{3}x from both sides. Anything subtracted from zero gives its negation.

$$y-2=-\frac{1}{3}x$$

Add 2 to both sides.

$$y=-\frac{1}{3}x+2$$