Solve for x
\left\{\begin{matrix}x=\frac{20\left(y+20\right)}{z}\text{, }&z\neq 0\\x\in \mathrm{R}\text{, }&y=-20\text{ and }z=0\end{matrix}\right.
Solve for y
y=\frac{xz-400}{20}
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zx=20y+400
The equation is in standard form.
\frac{zx}{z}=\frac{20y+400}{z}
Divide both sides by z.
x=\frac{20y+400}{z}
Dividing by z undoes the multiplication by z.
x=\frac{20\left(y+20\right)}{z}
Divide 400+20y by z.
20y+400=xz
Swap sides so that all variable terms are on the left hand side.
20y=xz-400
Subtract 400 from both sides.
\frac{20y}{20}=\frac{xz-400}{20}
Divide both sides by 20.
y=\frac{xz-400}{20}
Dividing by 20 undoes the multiplication by 20.
y=\frac{xz}{20}-20
Divide xz-400 by 20.
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