Solve xyxxxxxxxxxxx=4

$$xyxxxxxxxxxxx=4$$

Solve for y

$$y=\frac{4}{x^{12}}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply x and x to get x^{2}.

$$x^{2}yxxxxxxxxxx=4$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$x^{3}yxxxxxxxxx=4$$

To multiply powers of the same base, add their exponents. Add 3 and 1 to get 4.

$$x^{4}yxxxxxxxx=4$$

To multiply powers of the same base, add their exponents. Add 4 and 1 to get 5.

$$x^{5}yxxxxxxx=4$$

To multiply powers of the same base, add their exponents. Add 5 and 1 to get 6.

$$x^{6}yxxxxxx=4$$

To multiply powers of the same base, add their exponents. Add 6 and 1 to get 7.

$$x^{7}yxxxxx=4$$

To multiply powers of the same base, add their exponents. Add 7 and 1 to get 8.

$$x^{8}yxxxx=4$$

To multiply powers of the same base, add their exponents. Add 8 and 1 to get 9.

$$x^{9}yxxx=4$$

To multiply powers of the same base, add their exponents. Add 9 and 1 to get 10.

$$x^{10}yxx=4$$

To multiply powers of the same base, add their exponents. Add 10 and 1 to get 11.

$$x^{11}yx=4$$

To multiply powers of the same base, add their exponents. Add 11 and 1 to get 12.

$$x^{12}y=4$$

Divide both sides by x^{12}.

$$\frac{x^{12}y}{x^{12}}=\frac{4}{x^{12}}$$

Dividing by x^{12} undoes the multiplication by x^{12}.

$$y=\frac{4}{x^{12}}$$

Solve for x

$$x=\frac{\sqrt[6]{2}}{\sqrt[12]{y}}$$

$$x=-\frac{\sqrt[6]{2}}{\sqrt[12]{y}}\text{, }y>0$$