Solve xy-3x-2y-1=0

$$xy-3x-2y-1=0$$

Solve for x

$$x=\frac{2y+1}{y-3}$$

$$y\neq 3$$

Steps for Solving Linear Equation

Add 2y to both sides. Anything plus zero gives itself.

$$xy-3x-1=2y$$

Add 1 to both sides.

$$xy-3x=2y+1$$

Combine all terms containing x.

$$\left(y-3\right)x=2y+1$$

Divide both sides by y-3.

$$\frac{\left(y-3\right)x}{y-3}=\frac{2y+1}{y-3}$$

Dividing by y-3 undoes the multiplication by y-3.

$$x=\frac{2y+1}{y-3}$$

Solve for y

$$y=\frac{3x+1}{x-2}$$

$$x\neq 2$$

Steps for Solving Linear Equation

Add 3x to both sides. Anything plus zero gives itself.

$$xy-2y-1=3x$$

Add 1 to both sides.

$$xy-2y=3x+1$$

Combine all terms containing y.

$$\left(x-2\right)y=3x+1$$

Divide both sides by x-2.

$$\frac{\left(x-2\right)y}{x-2}=\frac{3x+1}{x-2}$$

Dividing by x-2 undoes the multiplication by x-2.

$$y=\frac{3x+1}{x-2}$$