Solve x3-7x^2+17x-15=0

$$x3-7 { x }^{ 2 } +17x-15=0$$

Solve for x_3

$$x_{3}=7x^{2}-17x+15$$

Solution Steps

Add 7x^{2} to both sides. Anything plus zero gives itself.

$$x_{3}+17x-15=7x^{2}$$

Subtract 17x from both sides.

$$x_{3}-15=7x^{2}-17x$$

Add 15 to both sides.

$$x_{3}=7x^{2}-17x+15$$

Solve for x (complex solution)

$$x=\frac{-\sqrt{28x_{3}-131}+17}{14}$$

$$x=\frac{\sqrt{28x_{3}-131}+17}{14}$$

Solve for x

$$x=\frac{-\sqrt{28x_{3}-131}+17}{14}$$

$$x=\frac{\sqrt{28x_{3}-131}+17}{14}\text{, }x_{3}\geq \frac{131}{28}$$