Solve x3+2x2-4x+23=0

$$x3+2x2-4x+23=0$$

Solve for x

$$x=\frac{2x_{2}+x_{3}+23}{4}$$

Steps for Solving Linear Equation

Subtract x_{3} from both sides. Anything subtracted from zero gives its negation.

$$2x_{2}-4x+23=-x_{3}$$

Subtract 2x_{2} from both sides.

$$-4x+23=-x_{3}-2x_{2}$$

Subtract 23 from both sides.

$$-4x=-x_{3}-2x_{2}-23$$

The equation is in standard form.

$$-4x=-2x_{2}-x_{3}-23$$

Divide both sides by -4.

$$\frac{-4x}{-4}=\frac{-2x_{2}-x_{3}-23}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$x=\frac{-2x_{2}-x_{3}-23}{-4}$$

Divide -x_{3}-2x_{2}-23 by -4.

$$x=\frac{x_{2}}{2}+\frac{x_{3}}{4}+\frac{23}{4}$$

Solve for x_2

$$x_{2}=-\frac{x_{3}}{2}+2x-\frac{23}{2}$$

Steps for Solving Linear Equation

Subtract x_{3} from both sides. Anything subtracted from zero gives its negation.

$$2x_{2}-4x+23=-x_{3}$$

Add 4x to both sides.

$$2x_{2}+23=-x_{3}+4x$$

Subtract 23 from both sides.

$$2x_{2}=-x_{3}+4x-23$$

The equation is in standard form.

$$2x_{2}=4x-x_{3}-23$$

Divide both sides by 2.

$$\frac{2x_{2}}{2}=\frac{4x-x_{3}-23}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x_{2}=\frac{4x-x_{3}-23}{2}$$

Divide -x_{3}+4x-23 by 2.

$$x_{2}=-\frac{x_{3}}{2}+2x-\frac{23}{2}$$