Solve x.2+8-y=y

$$x.2+8-y=y$$

Solve for x

$$x=10\left(y-4\right)$$

Steps for Solving Linear Equation

Subtract 8 from both sides.

$$x\times 0.2-y=y-8$$

Add y to both sides.

$$x\times 0.2=y-8+y$$

Combine y and y to get 2y.

$$x\times 0.2=2y-8$$

The equation is in standard form.

$$0.2x=2y-8$$

Multiply both sides by 5.

$$\frac{0.2x}{0.2}=\frac{2y-8}{0.2}$$

Dividing by 0.2 undoes the multiplication by 0.2.

$$x=\frac{2y-8}{0.2}$$

Divide -8+2y by 0.2 by multiplying -8+2y by the reciprocal of 0.2.

$$x=10y-40$$

Solve for y

$$y=\frac{x+40}{10}$$

Steps for Solving Linear Equation

Subtract y from both sides.

$$x\times 0.2+8-y-y=0$$

Combine -y and -y to get -2y.

$$x\times 0.2+8-2y=0$$

Subtract x\times 0.2 from both sides. Anything subtracted from zero gives its negation.

$$8-2y=-x\times 0.2$$

Subtract 8 from both sides.

$$-2y=-x\times 0.2-8$$

Multiply -1 and 0.2 to get -0.2.

$$-2y=-0.2x-8$$

The equation is in standard form.

$$-2y=-\frac{x}{5}-8$$

Divide both sides by -2.

$$\frac{-2y}{-2}=\frac{-\frac{x}{5}-8}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$y=\frac{-\frac{x}{5}-8}{-2}$$

Divide -\frac{x}{5}-8 by -2.

$$y=\frac{x}{10}+4$$