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xx+x\left(-5.6\right)+6.4=0
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.
x^{2}+x\left(-5.6\right)+6.4=0
Multiply x and x to get x^{2}.
x^{2}-5.6x+6.4=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-5.6\right)±\sqrt{\left(-5.6\right)^{2}-4\times 6.4}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -5.6 for b, and 6.4 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-5.6\right)±\sqrt{31.36-4\times 6.4}}{2}
Square -5.6 by squaring both the numerator and the denominator of the fraction.
x=\frac{-\left(-5.6\right)±\sqrt{31.36-25.6}}{2}
Multiply -4 times 6.4.
x=\frac{-\left(-5.6\right)±\sqrt{5.76}}{2}
Add 31.36 to -25.6 by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
x=\frac{-\left(-5.6\right)±\frac{12}{5}}{2}
Take the square root of 5.76.
x=\frac{5.6±\frac{12}{5}}{2}
The opposite of -5.6 is 5.6.
x=\frac{8}{2}
Now solve the equation x=\frac{5.6±\frac{12}{5}}{2} when ± is plus. Add 5.6 to \frac{12}{5} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
x=4
Divide 8 by 2.
x=\frac{\frac{16}{5}}{2}
Now solve the equation x=\frac{5.6±\frac{12}{5}}{2} when ± is minus. Subtract \frac{12}{5} from 5.6 by finding a common denominator and subtracting the numerators. Then reduce the fraction to lowest terms if possible.
x=\frac{8}{5}
Divide \frac{16}{5} by 2.
x=4 x=\frac{8}{5}
The equation is now solved.
xx+x\left(-5.6\right)+6.4=0
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.
x^{2}+x\left(-5.6\right)+6.4=0
Multiply x and x to get x^{2}.
x^{2}+x\left(-5.6\right)=-6.4
Subtract 6.4 from both sides. Anything subtracted from zero gives its negation.
x^{2}-5.6x=-6.4
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}-5.6x+\left(-2.8\right)^{2}=-6.4+\left(-2.8\right)^{2}
Divide -5.6, the coefficient of the x term, by 2 to get -2.8. Then add the square of -2.8 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-5.6x+7.84=-6.4+7.84
Square -2.8 by squaring both the numerator and the denominator of the fraction.
x^{2}-5.6x+7.84=1.44
Add -6.4 to 7.84 by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(x-2.8\right)^{2}=1.44
Factor x^{2}-5.6x+7.84. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-2.8\right)^{2}}=\sqrt{1.44}
Take the square root of both sides of the equation.
x-2.8=\frac{6}{5} x-2.8=-\frac{6}{5}
Simplify.
x=4 x=\frac{8}{5}
Add 2.8 to both sides of the equation.