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Solve for x
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x+10=3y
Add 3y to both sides. Anything plus zero gives itself.
x=3y-10
Subtract 10 from both sides.
-3y+10=-x
Subtract x from both sides. Anything subtracted from zero gives its negation.
-3y=-x-10
Subtract 10 from both sides.
\frac{-3y}{-3}=\frac{-x-10}{-3}
Divide both sides by -3.
y=\frac{-x-10}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{x+10}{3}
Divide -x-10 by -3.