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3x-\left(\sqrt{2}-1\right)=0
Multiply both sides of the equation by 3.
3x-\sqrt{2}-\left(-1\right)=0
To find the opposite of \sqrt{2}-1, find the opposite of each term.
3x-\sqrt{2}+1=0
The opposite of -1 is 1.
3x+1=\sqrt{2}
Add \sqrt{2} to both sides. Anything plus zero gives itself.
3x=\sqrt{2}-1
Subtract 1 from both sides.
\frac{3x}{3}=\frac{\sqrt{2}-1}{3}
Divide both sides by 3.
x=\frac{\sqrt{2}-1}{3}
Dividing by 3 undoes the multiplication by 3.