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x\left(x-1\right)=10\times 2
Multiply both sides by 2.
x^{2}-x=10\times 2
Use the distributive property to multiply x by x-1.
x^{2}-x=20
Multiply 10 and 2 to get 20.
x^{2}-x-20=0
Subtract 20 from both sides.
x=\frac{-\left(-1\right)±\sqrt{1-4\left(-20\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -1 for b, and -20 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-1\right)±\sqrt{1+80}}{2}
Multiply -4 times -20.
x=\frac{-\left(-1\right)±\sqrt{81}}{2}
Add 1 to 80.
x=\frac{-\left(-1\right)±9}{2}
Take the square root of 81.
x=\frac{1±9}{2}
The opposite of -1 is 1.
x=\frac{10}{2}
Now solve the equation x=\frac{1±9}{2} when ± is plus. Add 1 to 9.
x=5
Divide 10 by 2.
x=-\frac{8}{2}
Now solve the equation x=\frac{1±9}{2} when ± is minus. Subtract 9 from 1.
x=-4
Divide -8 by 2.
x=5 x=-4
The equation is now solved.
x\left(x-1\right)=10\times 2
Multiply both sides by 2.
x^{2}-x=10\times 2
Use the distributive property to multiply x by x-1.
x^{2}-x=20
Multiply 10 and 2 to get 20.
x^{2}-x+\left(-\frac{1}{2}\right)^{2}=20+\left(-\frac{1}{2}\right)^{2}
Divide -1, the coefficient of the x term, by 2 to get -\frac{1}{2}. Then add the square of -\frac{1}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-x+\frac{1}{4}=20+\frac{1}{4}
Square -\frac{1}{2} by squaring both the numerator and the denominator of the fraction.
x^{2}-x+\frac{1}{4}=\frac{81}{4}
Add 20 to \frac{1}{4}.
\left(x-\frac{1}{2}\right)^{2}=\frac{81}{4}
Factor x^{2}-x+\frac{1}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-\frac{1}{2}\right)^{2}}=\sqrt{\frac{81}{4}}
Take the square root of both sides of the equation.
x-\frac{1}{2}=\frac{9}{2} x-\frac{1}{2}=-\frac{9}{2}
Simplify.
x=5 x=-4
Add \frac{1}{2} to both sides of the equation.