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x^{2}+5x+5\left(x-2\right)=1
Use the distributive property to multiply x by x+5.
x^{2}+5x+5x-10=1
Use the distributive property to multiply 5 by x-2.
x^{2}+10x-10=1
Combine 5x and 5x to get 10x.
x^{2}+10x-10-1=0
Subtract 1 from both sides.
x^{2}+10x-11=0
Subtract 1 from -10 to get -11.
x=\frac{-10±\sqrt{10^{2}-4\left(-11\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 10 for b, and -11 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-10±\sqrt{100-4\left(-11\right)}}{2}
Square 10.
x=\frac{-10±\sqrt{100+44}}{2}
Multiply -4 times -11.
x=\frac{-10±\sqrt{144}}{2}
Add 100 to 44.
x=\frac{-10±12}{2}
Take the square root of 144.
x=\frac{2}{2}
Now solve the equation x=\frac{-10±12}{2} when ± is plus. Add -10 to 12.
x=1
Divide 2 by 2.
x=-\frac{22}{2}
Now solve the equation x=\frac{-10±12}{2} when ± is minus. Subtract 12 from -10.
x=-11
Divide -22 by 2.
x=1 x=-11
The equation is now solved.
x^{2}+5x+5\left(x-2\right)=1
Use the distributive property to multiply x by x+5.
x^{2}+5x+5x-10=1
Use the distributive property to multiply 5 by x-2.
x^{2}+10x-10=1
Combine 5x and 5x to get 10x.
x^{2}+10x=1+10
Add 10 to both sides.
x^{2}+10x=11
Add 1 and 10 to get 11.
x^{2}+10x+5^{2}=11+5^{2}
Divide 10, the coefficient of the x term, by 2 to get 5. Then add the square of 5 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+10x+25=11+25
Square 5.
x^{2}+10x+25=36
Add 11 to 25.
\left(x+5\right)^{2}=36
Factor x^{2}+10x+25. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+5\right)^{2}}=\sqrt{36}
Take the square root of both sides of the equation.
x+5=6 x+5=-6
Simplify.
x=1 x=-11
Subtract 5 from both sides of the equation.