Solve for y
\left\{\begin{matrix}y=\frac{x}{\sqrt{\sin(x)+x}}\text{, }&\sqrt{\sin(x)+x}\neq 0\text{ and }\sin(x)+x\geq 0\\y\in \mathrm{R}\text{, }&x=0\end{matrix}\right.
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y\sqrt{x+\sin(x)}=x
Swap sides so that all variable terms are on the left hand side.
\sqrt{\sin(x)+x}y=x
The equation is in standard form.
\frac{\sqrt{\sin(x)+x}y}{\sqrt{\sin(x)+x}}=\frac{x}{\sqrt{\sin(x)+x}}
Divide both sides by \sqrt{x+\sin(x)}.
y=\frac{x}{\sqrt{\sin(x)+x}}
Dividing by \sqrt{x+\sin(x)} undoes the multiplication by \sqrt{x+\sin(x)}.
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