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x+xy=16-y
Subtract y from both sides.
\left(1+y\right)x=16-y
Combine all terms containing x.
\left(y+1\right)x=16-y
The equation is in standard form.
\frac{\left(y+1\right)x}{y+1}=\frac{16-y}{y+1}
Divide both sides by 1+y.
x=\frac{16-y}{y+1}
Dividing by 1+y undoes the multiplication by 1+y.
y+xy=16-x
Subtract x from both sides.
\left(1+x\right)y=16-x
Combine all terms containing y.
\left(x+1\right)y=16-x
The equation is in standard form.
\frac{\left(x+1\right)y}{x+1}=\frac{16-x}{x+1}
Divide both sides by 1+x.
y=\frac{16-x}{x+1}
Dividing by 1+x undoes the multiplication by 1+x.