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x+2xy=83-y
Subtract y from both sides.
\left(1+2y\right)x=83-y
Combine all terms containing x.
\left(2y+1\right)x=83-y
The equation is in standard form.
\frac{\left(2y+1\right)x}{2y+1}=\frac{83-y}{2y+1}
Divide both sides by 1+2y.
x=\frac{83-y}{2y+1}
Dividing by 1+2y undoes the multiplication by 1+2y.
y+2xy=83-x
Subtract x from both sides.
\left(1+2x\right)y=83-x
Combine all terms containing y.
\left(2x+1\right)y=83-x
The equation is in standard form.
\frac{\left(2x+1\right)y}{2x+1}=\frac{83-x}{2x+1}
Divide both sides by 1+2x.
y=\frac{83-x}{2x+1}
Dividing by 1+2x undoes the multiplication by 1+2x.