Solve x+6x+3=x^2+6x+961

$$x+6x+3= { x }^{ 2 } +6x+961$$

Solve for x (complex solution)

$$x=\frac{-\sqrt{3831}i+1}{2}\approx 0.5-30.947536251i$$

$$x=\frac{1+\sqrt{3831}i}{2}\approx 0.5+30.947536251i$$

Steps Using the Quadratic Formula

Combine x and 6x to get 7x.

$$7x+3=x^{2}+6x+961$$

Subtract x^{2} from both sides.

$$7x+3-x^{2}=6x+961$$

Subtract 6x from both sides.

$$7x+3-x^{2}-6x=961$$

Combine 7x and -6x to get x.

$$x+3-x^{2}=961$$

Subtract 961 from both sides.

$$x+3-x^{2}-961=0$$

Subtract 961 from 3 to get -958.

$$x-958-x^{2}=0$$

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$-x^{2}+x-958=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute -1 for a, 1 for b, and -958 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-1±\sqrt{1^{2}-4\left(-1\right)\left(-958\right)}}{2\left(-1\right)}$$

Square 1.

$$x=\frac{-1±\sqrt{1-4\left(-1\right)\left(-958\right)}}{2\left(-1\right)}$$

Multiply -4 times -1.

$$x=\frac{-1±\sqrt{1+4\left(-958\right)}}{2\left(-1\right)}$$

Multiply 4 times -958.

$$x=\frac{-1±\sqrt{1-3832}}{2\left(-1\right)}$$

Add 1 to -3832.

$$x=\frac{-1±\sqrt{-3831}}{2\left(-1\right)}$$

Take the square root of -3831.

$$x=\frac{-1±\sqrt{3831}i}{2\left(-1\right)}$$

Multiply 2 times -1.

$$x=\frac{-1±\sqrt{3831}i}{-2}$$

Now solve the equation x=\frac{-1±\sqrt{3831}i}{-2} when ± is plus. Add -1 to i\sqrt{3831}.

$$x=\frac{-1+\sqrt{3831}i}{-2}$$

Divide -1+i\sqrt{3831} by -2.

$$x=\frac{-\sqrt{3831}i+1}{2}$$

Now solve the equation x=\frac{-1±\sqrt{3831}i}{-2} when ± is minus. Subtract i\sqrt{3831} from -1.

$$x=\frac{-\sqrt{3831}i-1}{-2}$$

Divide -1-i\sqrt{3831} by -2.

$$x=\frac{1+\sqrt{3831}i}{2}$$

The equation is now solved.

$$x=\frac{-\sqrt{3831}i+1}{2} x=\frac{1+\sqrt{3831}i}{2}$$

Steps for Completing the Square

Combine x and 6x to get 7x.

$$7x+3=x^{2}+6x+961$$

Subtract x^{2} from both sides.

$$7x+3-x^{2}=6x+961$$

Subtract 6x from both sides.

$$7x+3-x^{2}-6x=961$$

Combine 7x and -6x to get x.

$$x+3-x^{2}=961$$

Subtract 3 from both sides.

$$x-x^{2}=961-3$$

Subtract 3 from 961 to get 958.

$$x-x^{2}=958$$

Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.

$$-x^{2}+x=958$$

Divide both sides by -1.

$$\frac{-x^{2}+x}{-1}=\frac{958}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x^{2}+\frac{1}{-1}x=\frac{958}{-1}$$

Divide 1 by -1.

$$x^{2}-x=\frac{958}{-1}$$

Divide 958 by -1.

$$x^{2}-x=-958$$

Divide -1, the coefficient of the x term, by 2 to get -\frac{1}{2}. Then add the square of -\frac{1}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}-x+\left(-\frac{1}{2}\right)^{2}=-958+\left(-\frac{1}{2}\right)^{2}$$

Square -\frac{1}{2} by squaring both the numerator and the denominator of the fraction.

$$x^{2}-x+\frac{1}{4}=-958+\frac{1}{4}$$

Add -958 to \frac{1}{4}.

$$x^{2}-x+\frac{1}{4}=-\frac{3831}{4}$$

Factor x^{2}-x+\frac{1}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-\frac{1}{2}\right)^{2}=-\frac{3831}{4}$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x-\frac{1}{2}\right)^{2}}=\sqrt{-\frac{3831}{4}}$$

Simplify.

$$x-\frac{1}{2}=\frac{\sqrt{3831}i}{2} x-\frac{1}{2}=-\frac{\sqrt{3831}i}{2}$$

Add \frac{1}{2} to both sides of the equation.

$$x=\frac{1+\sqrt{3831}i}{2} x=\frac{-\sqrt{3831}i+1}{2}$$