Solve for x
x=-\frac{3\left(y-3\right)}{y+1}
y\neq -1
Solve for y
y=-\frac{x-9}{x+3}
x\neq -3
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x+xy=9-3y
Subtract 3y from both sides.
\left(1+y\right)x=9-3y
Combine all terms containing x.
\left(y+1\right)x=9-3y
The equation is in standard form.
\frac{\left(y+1\right)x}{y+1}=\frac{9-3y}{y+1}
Divide both sides by 1+y.
x=\frac{9-3y}{y+1}
Dividing by 1+y undoes the multiplication by 1+y.
x=\frac{3\left(3-y\right)}{y+1}
Divide 9-3y by 1+y.
3y+xy=9-x
Subtract x from both sides.
\left(3+x\right)y=9-x
Combine all terms containing y.
\left(x+3\right)y=9-x
The equation is in standard form.
\frac{\left(x+3\right)y}{x+3}=\frac{9-x}{x+3}
Divide both sides by 3+x.
y=\frac{9-x}{x+3}
Dividing by 3+x undoes the multiplication by 3+x.
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