Solve for x
x=7-5z-3y
Solve for y
y=\frac{7-5z-x}{3}
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x+5z=7-3y
Subtract 3y from both sides.
x=7-3y-5z
Subtract 5z from both sides.
3y+5z=7-x
Subtract x from both sides.
3y=7-x-5z
Subtract 5z from both sides.
3y=7-5z-x
The equation is in standard form.
\frac{3y}{3}=\frac{7-5z-x}{3}
Divide both sides by 3.
y=\frac{7-5z-x}{3}
Dividing by 3 undoes the multiplication by 3.
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