Solve x+2y+2z-4=0

$$x+2y+2z-4=0$$

Solve for x

$$x=4-2z-2y$$

Solution Steps

Subtract 2y from both sides. Anything subtracted from zero gives its negation.

$$x+2z-4=-2y$$

Subtract 2z from both sides.

$$x-4=-2y-2z$$

Add 4 to both sides.

$$x=-2y-2z+4$$

Solve for y

$$y=-\frac{x}{2}-z+2$$

Steps for Solving Linear Equation

Subtract x from both sides. Anything subtracted from zero gives its negation.

$$2y+2z-4=-x$$

Subtract 2z from both sides.

$$2y-4=-x-2z$$

Add 4 to both sides.

$$2y=-x-2z+4$$

The equation is in standard form.

$$2y=4-2z-x$$

Divide both sides by 2.

$$\frac{2y}{2}=\frac{4-2z-x}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$y=\frac{4-2z-x}{2}$$

Divide -x-2z+4 by 2.

$$y=-\frac{x}{2}-z+2$$