Solve for x
x=\frac{130-y}{3}
Solve for y
y=130-3x
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3x+50+y=180
Combine x and 2x to get 3x.
3x+y=180-50
Subtract 50 from both sides.
3x+y=130
Subtract 50 from 180 to get 130.
3x=130-y
Subtract y from both sides.
\frac{3x}{3}=\frac{130-y}{3}
Divide both sides by 3.
x=\frac{130-y}{3}
Dividing by 3 undoes the multiplication by 3.
3x+50+y=180
Combine x and 2x to get 3x.
50+y=180-3x
Subtract 3x from both sides.
y=180-3x-50
Subtract 50 from both sides.
y=130-3x
Subtract 50 from 180 to get 130.
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