Solve x+-25*3-45-1/2=-41/5

$$x+-25 \cdot 3-45- \frac{ 1 }{ 2 } = -4 \frac{ 1 }{ 5 }$$

Solve for x

$$x = \frac{1163}{10} = 116\frac{3}{10} = 116.3$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 10, the least common multiple of 2,5.

$$10x-250\times 3-450-5=-2\left(4\times 5+1\right)$$

Multiply -250 and 3 to get -750.

$$10x-750-450-5=-2\left(4\times 5+1\right)$$

Subtract 450 from -750 to get -1200.

$$10x-1200-5=-2\left(4\times 5+1\right)$$

Subtract 5 from -1200 to get -1205.

$$10x-1205=-2\left(4\times 5+1\right)$$

Multiply 4 and 5 to get 20.

$$10x-1205=-2\left(20+1\right)$$

Add 20 and 1 to get 21.

$$10x-1205=-2\times 21$$

Multiply -2 and 21 to get -42.

$$10x-1205=-42$$

Add 1205 to both sides.

$$10x=-42+1205$$

Add -42 and 1205 to get 1163.

$$10x=1163$$

Divide both sides by 10.

$$x=\frac{1163}{10}$$