x+ \frac{ 1 }{ 3 } = { 2 }^{ }
Solve for x
x = \frac{5}{3} = 1\frac{2}{3} \approx 1.666666667
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x+\frac{1}{3}=2
Calculate 2 to the power of 1 and get 2.
x=2-\frac{1}{3}
Subtract \frac{1}{3} from both sides.
x=\frac{6}{3}-\frac{1}{3}
Convert 2 to fraction \frac{6}{3}.
x=\frac{6-1}{3}
Since \frac{6}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.
x=\frac{5}{3}
Subtract 1 from 6 to get 5.
Examples
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{ x } ^ { 2 } - 4 x - 5 = 0
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Linear equation
y = 3x + 4
Arithmetic
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Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}