Solve xy=4+x^2

$$x y = 4 + x ^ { 2 }$$

Solve for y

$$y=x+\frac{4}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

The equation is in standard form.

$$xy=x^{2}+4$$

Divide both sides by x.

$$\frac{xy}{x}=\frac{x^{2}+4}{x}$$

Dividing by x undoes the multiplication by x.

$$y=\frac{x^{2}+4}{x}$$

Divide 4+x^{2} by x.

$$y=x+\frac{4}{x}$$

Solve for x (complex solution)

$$x=\frac{-\sqrt{y^{2}-16}+y}{2}$$

$$x=\frac{\sqrt{y^{2}-16}+y}{2}$$

Solve for x

$$x=\frac{-\sqrt{y^{2}-16}+y}{2}$$

$$x=\frac{\sqrt{y^{2}-16}+y}{2}\text{, }|y|\geq 4$$