Solve for b
\left\{\begin{matrix}b=\frac{xp^{3}-a}{p}\text{, }&p\neq 0\\b\in \mathrm{R}\text{, }&a=0\text{ and }p=0\end{matrix}\right.
Solve for a
a=p\left(xp^{2}-b\right)
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a+bp=xp^{3}
Swap sides so that all variable terms are on the left hand side.
bp=xp^{3}-a
Subtract a from both sides.
pb=xp^{3}-a
The equation is in standard form.
\frac{pb}{p}=\frac{xp^{3}-a}{p}
Divide both sides by p.
b=\frac{xp^{3}-a}{p}
Dividing by p undoes the multiplication by p.
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