Solve x-9-3*3

$$x - 9 - 3 \cdot 3$$

Evaluate

$$x-18$$

Solution Steps

Multiply 3 and 3 to get 9.

$$x-9-9$$

Subtract 9 from -9 to get -18.

$$x-18$$

Differentiate w.r.t. x

$$1$$

Steps Using Derivative Rule for Sum

Multiply 3 and 3 to get 9.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x-9-9)$$

Subtract 9 from -9 to get -18.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x-18)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$x^{1-1}$$

Subtract 1 from 1.

$$x^{0}$$

For any term t except 0, t^{0}=1.

$$1$$