Solve x-5y+2z+1=0

$$x - 5 y + 2 z + 1 = 0$$

Solve for x

$$x=5y-2z-1$$

Solution Steps

Add 5y to both sides. Anything plus zero gives itself.

$$x+2z+1=5y$$

Subtract 2z from both sides.

$$x+1=5y-2z$$

Subtract 1 from both sides.

$$x=5y-2z-1$$

Solve for y

$$y=\frac{x+2z+1}{5}$$

Steps for Solving Linear Equation

Subtract x from both sides. Anything subtracted from zero gives its negation.

$$-5y+2z+1=-x$$

Subtract 2z from both sides.

$$-5y+1=-x-2z$$

Subtract 1 from both sides.

$$-5y=-x-2z-1$$

Divide both sides by -5.

$$\frac{-5y}{-5}=\frac{-x-2z-1}{-5}$$

Dividing by -5 undoes the multiplication by -5.

$$y=\frac{-x-2z-1}{-5}$$

Divide -x-2z-1 by -5.

$$y=\frac{x+2z+1}{5}$$