Solve for x
x=3y+7
Solve for y
y=\frac{x-7}{3}
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x-7=3y
Add 3y to both sides. Anything plus zero gives itself.
x=3y+7
Add 7 to both sides.
-3y-7=-x
Subtract x from both sides. Anything subtracted from zero gives its negation.
-3y=-x+7
Add 7 to both sides.
-3y=7-x
The equation is in standard form.
\frac{-3y}{-3}=\frac{7-x}{-3}
Divide both sides by -3.
y=\frac{7-x}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{x-7}{3}
Divide -x+7 by -3.
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Limits
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