Solve x-31/20-31/20

$$x - 3 \frac { 1 } { 20 } - 3 \frac { 1 } { 20 }$$

Evaluate

$$x = -\frac{61}{10} = -6\frac{1}{10} = -6.1$$

Solution Steps

Multiply 3 and 20 to get 60.

$$x-\frac{60+1}{20}-\frac{3\times 20+1}{20}$$

Add 60 and 1 to get 61.

$$x-\frac{61}{20}-\frac{3\times 20+1}{20}$$

Multiply 3 and 20 to get 60.

$$x-\frac{61}{20}-\frac{60+1}{20}$$

Add 60 and 1 to get 61.

$$x-\frac{61}{20}-\frac{61}{20}$$

Since -\frac{61}{20} and \frac{61}{20} have the same denominator, subtract them by subtracting their numerators.

$$x+\frac{-61-61}{20}$$

Subtract 61 from -61 to get -122.

$$x+\frac{-122}{20}$$

Reduce the fraction \frac{-122}{20} to lowest terms by extracting and canceling out 2.

$$x-\frac{61}{10}$$

Expand

$$x = -\frac{61}{10} = -6\frac{1}{10} = -6.1$$

Solution Steps

Multiply 3 and 20 to get 60.

$$x-\frac{60+1}{20}-\frac{3\times 20+1}{20}$$

Add 60 and 1 to get 61.

$$x-\frac{61}{20}-\frac{3\times 20+1}{20}$$

Multiply 3 and 20 to get 60.

$$x-\frac{61}{20}-\frac{60+1}{20}$$

Add 60 and 1 to get 61.

$$x-\frac{61}{20}-\frac{61}{20}$$

Since -\frac{61}{20} and \frac{61}{20} have the same denominator, subtract them by subtracting their numerators.

$$x+\frac{-61-61}{20}$$

Subtract 61 from -61 to get -122.

$$x+\frac{-122}{20}$$

Reduce the fraction \frac{-122}{20} to lowest terms by extracting and canceling out 2.

$$x-\frac{61}{10}$$