Solve x-2-20-10=

$$x - 2 - 20 - 10 =$$

Evaluate

$$x-32$$

Solution Steps

Subtract 20 from -2 to get -22.

$$x-22-10$$

Subtract 10 from -22 to get -32.

$$x-32$$

Differentiate w.r.t. x

$$1$$

Steps Using Derivative Rule for Sum

Subtract 20 from -2 to get -22.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x-22-10)$$

Subtract 10 from -22 to get -32.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x-32)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$x^{1-1}$$

Subtract 1 from 1.

$$x^{0}$$

For any term t except 0, t^{0}=1.

$$1$$