Solve x-12leq3(x-2)+x

$$x - 12 \leq 3 ( x - 2 ) + x$$

Solve for x

$$x\geq -2$$

Solution Steps

Use the distributive property to multiply 3 by x-2.

$$x-12\leq 3x-6+x$$

Combine 3x and x to get 4x.

$$x-12\leq 4x-6$$

Subtract 4x from both sides.

$$x-12-4x\leq -6$$

Combine x and -4x to get -3x.

$$-3x-12\leq -6$$

Add 12 to both sides.

$$-3x\leq -6+12$$

Add -6 and 12 to get 6.

$$-3x\leq 6$$

Divide both sides by -3. Since -3 is negative, the inequality direction is changed.

$$x\geq \frac{6}{-3}$$

Divide 6 by -3 to get -2.

$$x\geq -2$$