Solve x-3/z=9

$$x - \frac { 3 } { z } = 9$$

Solve for x

$$x=9+\frac{3}{z}$$

$$z\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by z.

$$zx-3=9z$$

Add 3 to both sides.

$$zx=9z+3$$

Divide both sides by z.

$$\frac{zx}{z}=\frac{9z+3}{z}$$

Dividing by z undoes the multiplication by z.

$$x=\frac{9z+3}{z}$$

Divide 9z+3 by z.

$$x=9+\frac{3}{z}$$

Solve for z

$$z=-\frac{3}{9-x}$$

$$x\neq 9$$

Steps for Solving Linear Equation

Variable z cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by z.

$$zx-3=9z$$

Subtract 9z from both sides.

$$zx-3-9z=0$$

Add 3 to both sides. Anything plus zero gives itself.

$$zx-9z=3$$

Combine all terms containing z.

$$\left(x-9\right)z=3$$

Divide both sides by x-9.

$$\frac{\left(x-9\right)z}{x-9}=\frac{3}{x-9}$$

Dividing by x-9 undoes the multiplication by x-9.

$$z=\frac{3}{x-9}$$

Variable z cannot be equal to 0.

$$z=\frac{3}{x-9}\text{, }z\neq 0$$